Subido por paty_2402

Ejercicio 2

Anuncio
serico"a
⑤
Egg
61
=
Cnezocoss
(0
⑭
is
x0
"m
J
6.6147
3.52x10-3
y=
2
6.63i
YN +
J'
1
YN +
1
T
p
ast
*
h
x'0
19mol
Inerte:
n
3atm
(N(1
A
D
Y
LN =
*
N=
L
N
0.176
punto
se
59.5
=
19mo
n
X N: 0.2464
mas alto
busca
Airey Agua
=
=
lgmol
=
gas y soluto
100C
=
0.16
=
89
=
6'GN
kgmol
=
wi
5
6'65
6N + 1 188
↓=59.S
12
en
0
=
L1 L(
L2
6:64
HCl
=
98.1. alimentado
primero
HC1 + alre
fluso
YN+ 1
fluso aqua
flusoaire" 1.4 fluare
agoa
=
=
min
Li
1.4
YN + 1 (1
=
s'min
6
6N + 1(1 YN + 1)
-
188"9M0(1
=
-
0.15)
8g19m
=
yn +
1)
0.15
=
=
-
=
1
-
0.15
0.176
98%.
Sialimento
>
LN
et
100%HiS
serecuper
solo
2%.>61R
entences
Moles
11
Moles incrte
=
((Y(n
Holenxe
+
1)6
=
6'
+(1x5%0.82_10.173183"))0.02
89 kgmol
63
R
y = 3.52x10-3
()
(4 "Xmax
p= 2280 mmHg
gmol
x
=
Pi
HCI
y
gmol HO
=
p
O
1100BSON 18gHcO gMolerr
-
p
O
0.042904
2.5578x18
0.09394S
7.0175x101.
0.23178
5.2023x16
0.27764
0.0253
0.37893
0.1138
0.38761
0.5833
I
6
0.345
=
Y'N+1
21
=
min
=
-
X'max
-
0.176
-
Y'r
X'O
3.52x18-3
0.176
0.345-O
2
I
=
0.58
0. 746
1:
=
1.4(0.5)
0.76'=
Moles
xn
0.7(8g
His
moles
=
0.77.j
=
on
Sq.g
=
Kgmo
0.98(6'yn+1
IN
de
min
19m1)
=
(3
agre
+('x50.98/8s "90(0.1731)
=
=
59.5
0.2464
7
6
8863x10-Y
0.15583
x max
5
-
KgM0
-
3
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