RC networks applications by Jorge E. Sousa Ceballos Reduce Alterna tension The application is easy Alternating Voltage R-C Network Alternating Voltage with reduced amplitude The electrical impedance (Z) is the total opposition that a circuit presents to the alternating current. The impedance is measured in ohms or ohms and may include resistance (R), inductive reactance (XL) and capacitive reactance (XC) TOTAL IMPEDANCE Calculate the total impedance Z using the Pythagorean theorem. Capacitor without polarity Ue : AC input voltage R : Resistor C : Capacitor without polarity Ua : AC ouput Voltage Step 1 Here we assume values for the frequency of Work, Capacitor and Resistor. f = 60 Hz C= 16/10^6 farads ; R = 5 x 10^3 ohms pi = 3,141 Z = √(R^2 + Xc^2) Impedance of the RC network . 1 1 Xc = = 2𝜋𝑓𝐶 (2)∗(3.14)∗(60)∗(16∗ 10−6 ) Xc = 1658.7 ohms = 1.6587 * 10^3 ohms Z = √((1658.7)^2 + ((5000)^2 ); Z = 5267.94 ohmios = 5.27 x 10^3 ohms. Step 2 A matter of interest is how much current You can supply us with the R-C network. We calculate the current (I) with the following: ╺ ╺ If : Ue = 240 volts alternating current So: I = V/Z; 240/5.27 x 10^3 I = 45 * 10^-3 amps Step 3 Calculate the voltage along R ╺ R: VR = I * R ╺ VR = 45*10^-3 * 5 x 10^3 ╺ VR = 225.15 volts Calculate the voltage along C: ╺ Vc = Xc * I = 1.6587 * 10^3 * 45 *10^-3 = 76.64 V √(Vc^2 + VR^2) = 237V ≈ 240V, network voltage CONCLUSIONS An alternating voltage source can be reduced by the connection of a capacitor and a series resistor through her. The current flowing through the circuit can be calculate as the source voltage (V) divided by the impedance circuit total (Z). Therefore, the voltage along the resistance is the value of the resistor (ohms) by the circuit current (I) The impedance (Z) is the sum of the capacitive impedance (Xc) and the resistance (R). https://es.wikipedia.org/wiki/CircuitoRC
