Subido por Jorge Sousa

# RC networks

Anuncio ```RC networks
applications
by Jorge E. Sousa Ceballos
Reduce
Alterna tension
The application is easy
Alternating
Voltage
R-C Network
Alternating
Voltage with
reduced
amplitude
The electrical impedance (Z)
is the total opposition that a circuit presents to
the alternating current. The impedance is
measured in ohms or ohms and may include
resistance (R), inductive reactance (XL)
and capacitive reactance (XC)
TOTAL
IMPEDANCE
Calculate the total impedance Z
using the Pythagorean theorem.
Capacitor without polarity
Ue : AC input voltage
R : Resistor
C : Capacitor without polarity
Ua : AC ouput Voltage
Step 1
Here we assume values for the frequency
of Work, Capacitor and Resistor.
f = 60 Hz
C= 16/10^6 farads ; R = 5 x 10^3 ohms
pi = 3,141
Z = √(R^2 + Xc^2)
Impedance of the RC network .
1
1
Xc =
=
2𝜋𝑓𝐶 (2)∗(3.14)∗(60)∗(16∗ 10−6 )
Xc = 1658.7 ohms = 1.6587 * 10^3 ohms
Z = √((1658.7)^2 + ((5000)^2 ); Z = 5267.94 ohmios = 5.27 x 10^3 ohms.
Step 2
A matter of interest is how much current
You can supply us with the R-C network.
We calculate the current (I) with the following:
╺
╺
If : Ue = 240 volts alternating current
So: I = V/Z; 240/5.27 x 10^3
I = 45 * 10^-3 amps
Step 3
Calculate the voltage along R
╺ R: VR = I * R
╺ VR = 45*10^-3 * 5 x 10^3
╺ VR = 225.15 volts
Calculate the voltage along C:
╺ Vc = Xc * I = 1.6587 * 10^3 * 45 *10^-3 = 76.64 V
√(Vc^2 + VR^2) = 237V ≈ 240V, network voltage
CONCLUSIONS
An alternating voltage source can be reduced by the
connection of a capacitor and a series resistor through her.
The current flowing through the circuit can be calculate as the
source voltage (V) divided by the impedance circuit total (Z).
Therefore, the voltage along the resistance is the value of
the resistor (ohms) by the circuit current (I) The impedance (Z)
is the sum of the capacitive impedance (Xc) and the resistance (R).
https://es.wikipedia.org/wiki/CircuitoRC
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