cos(x)

Temel Formuller
sin2x+cos2x=1
cos(x+y)=cosx cosy - sinx siny
sin(x+y)=sinx cosy + siny cosx
sin(-x)=- sinx
cos(-x)=cos(x)
tan(-x)=-tan(x)
cos(x-y)=cosx cos y + sinx sin y
sin(x-y)=sinx cosy - siny cos x
1
[cos(x+y) +cos(x-y)]
2
1
sinx siny = [ cos(x-y)- cos(x+y)]
2
1
sinx cosy = [ sin(x+y)+ sin(x-y)]
2
cosx cosy=
cos(x+90)=– sinx
cos(x- 90)= sinx
sin(x+ 90)= cosx
sin(x- 90)= -cosx
cos(90-q)= sinq
sin(90-q)= cosq
cos(2x) = 2cos2x -1
1
2
cos2x = [ 1+cos(2x)]
cos(2x) =1- 2sin2x
1
2
tan x =
sin x =
cos x =
q
-1
2
q
cos q = 1-2sin2
2
q
q
sinq =2 sin cos
2
2
1
3
3
sin q= = - sin(3q) + sin q
4
4
cos q = 2cos2
sin(3q)= -4sin3q +3sinq
cos3q= =
1
3
cos3q + cosq
4
4
cos3q=4 cos3q -3 cosq
tan x + tan y
1 − tan x tan y
tan x − tan y
tan( x − y ) =
1 + tan x tan y
2 tan x
tan(2 x) =
1 − tan 2 x
q
2 tan
2
tan(q) =
2 q
1 − tan
2
tan( x + y ) =
1 − sin 2 x
tan x
1 − cos2 x
cos x
=
1 + tan 2 x
1
1 + tan 2 x
x
1 − tan
2
cos x =
2 x
1 + tan
2
x
2 tan
2
sin x =
2 x
1 + tan
2
------------------ ---Basit hatirlama teknigi
1 + x2
x
q
1
x
tan q = =x
1
sin q = x
1+ x
sin2x = [ 1-cos(2x)]
sin2x =2 sinx cosx
sin x
cos q =
=
2
1
1+ x
=
2
tan q
1 + tan 2 q
1
1 + tan 2 q
sin 2q=2sin q cos q=
2q=p q=p/2
sin p =
2 tan
p
2
1 + tan 2
p
2
2x
= 2 tan q2
2
1 + x 1 + tan q