DISEÑO DE FILTROS A –60 dB/dec

DALCAME
www.dalcame.com
__________________________________________________________
DISEÑO DE FILTROS A –60 dB/dec
FILTRO PASABANDA CON Fl=0.1Hz y Fh=100Hz
Procedimiento de diseño:
a. Escoja el Amplificador Operacional: LF356
con RRMC=100db,
entrada=1012Ω
b. B=100Hz-0.1Hz=99.9Hz
c.
Fr = (100 Hz )(0.1Hz ) = 3.1622 Hz
(99.9 Hz ) 2
99.9 Hz
d. Fl =
+ (3.1622 Hz ) 2 −
= 0.0999 Hz
4
2
3.1622 Hz
= 0.0316 = Banda Ancha
e. Q =
99.9 Hz
Banda Ancha
Pasabajas Fh=100Hz
a. C3 = 0.1µ F
b.
f c = 100 Hz
R = 15.915k Ω
0.1µ F
C1 =
= 50000 pF = 0.05µ F
d.
2
C2 = 2(0.1µ F ) = 200000 pF = 0.2 µ F
c.
e.
f.
R1 = R2 = R3 = 15.915k Ω
RF 1 = 2(15.915k Ω) = 31.83k Ω
RF 2 = 15.915k Ω
Pasaaltas fl=0.1Hz
a. C3 = 10 µ F
b.
c.
d.
e.
f.
f c = 0.1Hz
1
R3 =
= 159.154k Ω
2π f c C
159.154k Ω
R2 =
= 79.57 k Ω
2
R1 = 318.308k Ω
RF 1 = 318.308k Ω
RF 2 = 159.154k Ω
Impedancia
DALCAME
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__________________________________________________________
FILTRO PASABAJAS CON fc=100Hz
a. Amplificador Operacional: LF356
b. C3 = 0.1µ F
c.
d.
e.
f.
C3
= 50000 pF = 0.05µ F
2
C2 = 2C3 = 200000 pF = 0.2 µ F
1
R=
= 15.915k Ω
2π f c C3
R1 = R2 = R3 = R = 15.915k Ω
RF 1 = 2(15.915k Ω) = 31.83k Ω
RF 2 = 15.915k Ω
C1 =
FILTRO PASAALTAS CON fc=0.1Hz
a. Amplificador Operacional: LF356
b. C = 10 µ F
DALCAME
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__________________________________________________________
1
= 159.1549k Ω
2π f c C
d. R1 = 2(159.1549k Ω) = 318.3098k Ω
159.1549k Ω
e. R2 =
= 79.5774k Ω
2
RF 1 = 318.3098k Ω
c.
f.
R3 =
RF 2 = 159.1549k Ω
FILTRO RECHAZA BANDA CON fr=120Hz y B=6Hz
a. Amplificador Operacional: LF356
b.
c.
d.
fl =
36
6
B2
B
+ fr 2 − =
+ 1202 − = 117.04 Hz
4
2
4
2
B = fH − fL
f H = B + f L = 123.04 Hz
C = 1µ F
f r = (123.04 Hz )(117.04 Hz ) = 120 Hz
120
f. Q =
= 20
6
0.1591
0.1591
=
= 26.517k Ω
g. R =
BC
(6)(1µ F )
R
26.517k Ω
=
= 33.19Ω
h. Rr =
2
2Q − 1 2(20) 2 − 1
e.
DALCAME
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__________________________________________________________