5.4.16 ∫ sec t(sec t + tan t)

5.4.16
Z
sec t(sec t + tan t) dt = tan t + sec t + C
5.4.17
Z
5.4.16
Z
5.4.32
Z
4
(1 + tan2 α) dα = tan α
sin 2x
dx =
sin x
√
1
Z
2 cos x dx = 2 sin x
4
y−y
1
dy = −2y 2 − ln y = 1 − ln 4
2
y
1
5.4.38
Z
π/3
0
sin θ + sin θ tan2 θ
dθ =
sec2 θ
Z
10
Z
5.4.40
Z
5.4.41
√
Z
3/2
0
1
√
dr =
1 − r2
Z
π/3
0
π/3
1
=
sin θ dθ = − cos θ
2
0
10
10
2ex
= 40
dx = 2x
x
e
−10
0
2ex
dx =
sinh x + cosh x
−10
π/3
−10
1
d sin θ =
| cos θ|
Z
π/3
dθ =
0
π
3
5.4.45
Z
2
2
Z
(x − 2|x|) dx =
Z
−1
5.4.49
Z
area =
0
Z
0
4
3x dx =
−1
0
5.4.63
0
−x dx +
2
2
0
3 2 7
−x2 +
=−
x
2 0 2 −1
2
2
4
1 3 (2y − y ) dy = (y − y ) =
3
3
0
2
2
4
4 3 32
2
2
9 + 2 x dx = (9x + x ) = 36 +
= 46
3
3
3
0
√
1