Respuestas de la Guía Nº 1: ERRORES INSTRUMENTALES

UNMDP
Facultad de Ingeniería
Departamento de Ingeniería Eléctrica
Cátedra: Mediciones Eléctricas I
Respuestas de la Guía Nº 1: ERRORES INSTRUMENTALES - 1º PARTE
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1.a. αmed = 63 divisiones
b. Einst(I) = ±0.15[mA]
c. Elect(I) = ±0.02[mA]
d. Etotal(I) = ±0.17[mA]
e. I = (12.60 ± 0.17)[mA] = (1260 ± 17). 10−2 [mA]
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A
2.a. Ce = 0.1 [div]
b. Vm = 4.5[A]
c. e%(I) = 0.67% (sin considerar el error de lectura)
d.
αmed = 10.1 div ⟹ I = (1.01 ± 0.03)[A] = (101 ± 3 ). 10−2 [A]
αmed = 35 div ⟹ I = (3.50 ± 0.03)[A] = (350 ± 3 ). 10−2 [A]
αmed = 45 div ⟹ I = (4.50 ± 0.03)[A] = (450 ± 3 ). 10−2 [A]
αmed = 58.3 div ⟹ I = (5.83 ± 0.03)[A] = (583 ± 3 ). 10−2 [A]
e.
αmed = 10.1 div ⟹ e%(I) = 2.97%
αmed = 35 div ⟹ e%(I) = 0.86%
αmed = 45 div ⟹ e%(I) = 0.67%
αmed = 58.3 div ⟹ e%(I) = 0.51%
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3.a. e%(1) = 1.8%
e%(2) = 3.0%
b. Vmed = 41.7[V]
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Respuestas de la Guía Nº 1: ERRORES INSTRUMENTALES - 1º PARTE
1
UNMDP
Facultad de Ingeniería
Departamento de Ingeniería Eléctrica
4. e%(1/4) = 8%
e%(3/4) = 2.67%
Cátedra: Mediciones Eléctricas I
e%(1/2) = 4%
e%(1/8) = 16%
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5. Imed = 6.4[A]
Einst(I) = ±0.2[A]
Elect(I) = ±0.04[A]
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6.a. Tensión.
b. 500[V]
c. 400[V]
d. Instrumento de hierro móvil.
e. 10[V/div]
f. Posición vertical
g. Einst(U) = 7.5[V]
h. Elect(U) = 2[V]
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7.a. Einst(U) = ±0.079[V]
b. Eres(U) = ±0.001[V]
c. Etotal(U) = ±0.080[V]
d. U = (15.69 ± 0.08)[V] = (1569 ± 8). 10−2 [V]
e. Uind = 5.540[V]
f. Einst(U) = ±0.0287[V]
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8.a. Einst(I) = ±0.07[A]
b. Eres(I) = ±0.01[A]
c. Einst(I) = ±0.04[A]
Respuestas de la Guía Nº 1: ERRORES INSTRUMENTALES - 1º PARTE
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