Subido por Mario Alberto Negrón Saucedo

Beam Statics Calculation Example

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EJEMPLO
15 KN
20 UN
Ry 1
B
-
11 1
,
1
I 1408
↑
RyA
1R2
7
RXA
x
1111
,
I
I
I
+
i
I
t
V
S
!
20 cos 40
15 32 AN
.
[Fx 0
Mmax
=
Rye
Rya
0
R xx + 15 32kN 0
=
.
-
39 75
Az
.
15 32 kN
.
R2
·
=
=
-
29 250
.
=
=
-
10
-
=
=
.
"15KN
.
IMA g
=
14 6 AN
.
Ryb (11) (12 85)(2) (13)(8) 0
+
.
+
Ry -13 24 AN
=
.
.
5u2
39 75r
12 85 AN
+
=
RXa + RX ,
=
=
Rye 20 sen 40
EFy 0
=
RXa
=
"
-
+
A
.
Az
I
=
14 6
=
I
↑
Rxy
max
i
-
=
RyB
As
-
RX ,
↑
B
An
:
&
3
6
2
:
?
-
EJEMPLO
-
Ri
↓
30 UN
504N
1
I
Rya
↑
↓
v
↓
V
/
·
-
IIII
1 1 25
.
>
Ry
Di
=
↓
3
. G
+
75hN
I
. 8
4
2
↑
RXA
.
&
75
Ry B
3) 1
=
V
~
-
IIIII
-
V
Re
Mc (30) (2 75)
=
.
X : Im
R2
=
+
82 5 AN
.
[FX 0
=
RXA 0
=
[Fy O
=
RYa-Ry-R2 Ryp 0
+
Ryn
=
=
31 7N
+
.
IMa 0
=
Ryb (8 25) (75) (3 25) 182 5) (9 625) 0
-
-
=
.
.
RyB
=
+
.
125 80 kN
.
.
X=
=
2
1 375 m
.
#
EJE MPLo
20kN/m
↓
↓
↓
↓ 30KNIM
Re
!
↓
-
>
I
↑
!
~
↓ R3
Ry
=
=
(2
Y
20 AN
X=
+
14
=
,
"
=
/3 m
V
~
-
1/1/
I
1 60
2
.
I
75
I
2
I
.S
3
M
I
RyB
RyA
Ry
v
V
RXA
I
2
15XN/m
-
Re (30) (2 73)
e
Ry=
R2 82 5 AN
Xz 1 375m
R3
=
.
=
+
=
.
.
=
(3 3)
.
+
26 25 kN
.
[FX 0
=
RXA 0
=
[Fy 0
=
Rya-Ry-Re RyB-Ry 0
+
Ryn
+
=
=
52 14 AN
.
.
[Ma 0
=
RyB (6 33) (20) (0 66) (82 5)(2 975) (26
.
Ryp
=
+
76 61hN
.
.
.
.
25) (8 68) 0
=
-
-
-
.
.
.
3)
Y 113
.
:
:
g
2 33 m
.
EJEMPL
↓
↓
Re
↓!III
↓
↓
>
--
1/1/
3
I
=
Ry
=
2
+
9 63 AN
.
1R2
+
11//
↓
↓
-
7
↑ RyA
↑
.
Ry
RXA
x
I
=
.
↓
↓
!
I
=
424M/m
X1 6
<6 42)(3)
R
N/m
4
I
RyB
Xz
=
15kN/m
[FX 0
=
Xi ((3
-
RX = 0
=
X , 2m
=
[Fy 0
=
R
Re
(4)
=
+
=
17 16 kN
.
Y2=
Xz 2 66m
=
.
-
R Rya Rz RyB Rz 0
+
+
-
-
=
Rya -76 85kN
=
.
Ma 0
=
Rg (15) (t)
=
Ig E
:
(9 63) (1) (13) (3 5) + Ry (7) (17 16) (9 66) O
=
-
-
.
.
.
.
R3
:
+
185hN
Yg 3 Sm
:
.
RyB
=
+
208 644N
.
EJEMPLO
R
Rya
↑
n I
40 ha
↓
A
2x2
↓
-y
RXA
>
-
I
I
I
.
RS2xdx- 2
R2
=
+
I
4
3
2 S
Xz
RXA
=
=
0
[Fy c
0
Rya-Ry R2 =
Ma
+
595 74AN
"
↓
>
-
Ry
Ry
(3)
1
=
11 25 &N
+
=
.
4)
Re =
Re
35KN/m
B
-11/
-
3
7
↑
I
4
I
20 UN
I
I
8. 4
8
Xz
17
=
.
54N/m
=
3
X ,.
[Mc 0
[Fy 0
=
=
* = 2m
(105)(3) + RyB (4 40) (201(8 66) 0
Rya-11 25-122 5 110 95-20 8
RyB
Rya
-
-
Yz (4)
-z 2 66m
=
+
+
=
.
.
.
110 95 hN
.
=
42 8 kN
+
=
.
.
IMA 0
=
+
-
·
Rz
(17 5)(7)
.
Xz :
-
Rz
=
+
122 5 AN
.
Xz
=
3 5m
.
Ma
=
+
.
·
.
.
139 97kN m
.
.
-
.
=
.
.
MA- (11 25) (2) (122 5) (6 5) (110 95) (8 40) (20)) /2 66) =
=
I
4
Ryß
=
+
=
R3
C
=
Xz 104/m
5mN/m
MPLO
I
I
=
kNom
⑧
I
0
1
11d1 ↳
RXA
I
=
.
.
.
↓
d
A
.
17m
1565 74)(8 17)
4640 3958
=
Re
↓
↑ Rya
-
.
Ma
.
(40)(2 3)
-
EJE
xy= 7
.
=
-
=
8
=
IM 0
=
Rya
5
+-
555 744N
.
[FX
.
MPLO
,
EJE
↓
↳
A
X
S//
D
↓
I
.
3
Ry
Ry
143)
X
4 5 T
Y=
=
=
.
s
=
Ry =
-
13
Y g 1 33m
*
C
I
I
4
SY5Ry]
RXA
Rya-R
Ryt
=
=
S
=
1. 5
-
1
Re + RyB-Rg + Ryc 0
=
12 5 + 14 7875
-
Ryc
.
=
-
.
.
1 5
=+
2T/m
T
S Il
[Fy O
=
R3
B
EFX g
5)
X
11/19
IMD 0
2m
RT
↓
↓ ddm
-
2
=
=
I
·
3T/m
-
3
=
Re
Si/m i
=
2+
Ryc
=
0
-1 7875
.
3 3m
=
.
[Mc 0
=
:
25
=
-
-
.
Rya(9)
+
R2(5 7)
RyB(4)
-
.
+
Ry(0 7) 0
=
.
(1 5)(9) (12 5) (5 7) + (2)(0 7) RyB (4)
+
=
·
.
.
.
71 25 + 1 4
.
.
Ry B
+ 14
=
.
-
13 5
RyB(4)
:
.
7875T
EJEMPLO
R2
↓
↓
↓
I
I
3T/mf
R1
↓
I
in2x
↓
L
I
&
-E
I
S
=
3
.5
!
-
A 1/1/l -
↑ Rya
I
=
Ri
=
+
4
L
1
I
RS2x
R2
=
2[] *
=
0
3
=
Rxa YT
Rya
7
RyB
=
+
=
1
Ma 0
EFy O
Rya-Ry-R2 RyB 0
.
=
↑
2
RXA RXz
3152 5 T
*
I
S
=
+
.
-
-
.
2S, d
-
-
[Fx
.
20 4 T
+
4
IIIIIB
=
.
1T/m
-
Exi-"
X1 3 4m
Ri (3) (6 8)
Rx3
1057 29T
.
=
RyB(11) (20 4)(3 4)
-
-
.
.
RyB
=
2115 67T
.
(3152 5) (7 36)
.
.
=
0
MPLO
EJE
-
3
.
5
'3N
&
↑
My
↓
2T/m
I
↓
+
-RXA
.5
3
EMc
Ri
12 2 T
Ryp(4)
3 05m
RyB
.
1
+
=
.
=
.
5
2
,
=
=
[FX
0
+
-
=
4
[Fy 0
0
=
(2((2 5) 0
RX1 1 0
Rya
1 25 AN
Rxa
Rya
=
=
.
.
=
+ 25
EJE MP
-
0 43 + RyB
.
=
-
0 82T
.
Lo
!
-11
-
21
-
I
L
-
-
2
4
-
TI/
-
-
/II
I
F
F2
=
=
I
4
I
4
[Fy 0
[Fx
RyB(8) Fz(3) Fy(2) 0
RyBRya-F1 =
Rx1 Fz 0
Ry (8)
3 25 + Rya-16 0
Rxa
16T
IM 0
25
=
=
+
RyB
=
+
-
2 (3)
+
3 25T
.
-
=
16(2)
=
0
=
.
Rya
=
+
12 755
.
=
0
=
-
=
+
-
&
I
7
3
-
#B
Rya
M (2) (6 10)
=
I
-
R2
!
---A
I
⑳ C
2 ton
I
↓
↑
m
"
↓
III
.
2T
=
0
↑ RyB
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