𝑋𝑃´ + 2𝑋𝐶 + 𝑋𝑃 = 𝐿 𝐹𝑦 = 𝑚𝑎𝑦 𝑉𝑃´ + 2𝑉𝐶 + 𝑉𝑃 = 0 𝑇 − 𝑊 = 𝑚𝑎 𝑎𝑃´ + 2𝑎𝐶 + 𝑎𝑃 = 0 𝑇 = ( 32.2 ) ( 𝑎𝐶 = −2−3 2 = −2.5 𝐹 = 161.64𝐿𝐵 𝑚 ´ 𝑠 360𝑙𝑏 2.5𝑚 ´) + 𝑠 𝑇 = 323.29𝑙𝑏 300𝑙𝑏
𝑋𝑃´ + 2𝑋𝐶 + 𝑋𝑃 = 𝐿 𝐹𝑦 = 𝑚𝑎𝑦 𝑉𝑃´ + 2𝑉𝐶 + 𝑉𝑃 = 0 𝑇 − 𝑊 = 𝑚𝑎 𝑎𝑃´ + 2𝑎𝐶 + 𝑎𝑃 = 0 𝑇 = ( 32.2 ) ( 𝑎𝐶 = −2−3 2 = −2.5 𝐹 = 161.64𝐿𝐵 𝑚 ´ 𝑠 360𝑙𝑏 2.5𝑚 ´) + 𝑠 𝑇 = 323.29𝑙𝑏 300𝑙𝑏