lOMoARcPSD|180 699 47 Practice Worksheet for Significant Figures 1. State the number of significant digits in each measurement. 1) 2804 m 4 4) 0.003068 m 7) 750 m 2.84 km 3 3) 5.029 m 4 5) 4.6 x 105 m 2 6) 4.06 x 10-5 m 3 8) 75 m 2 or 3 75.00 m 10) 4 2) 2 11) 75,000.0 m 6 4 9) 75,000 m 2, 3, 4, or 5 12) 10 cm 1 or 2 2. Round the following numbers as indicated: To four figures: 3.682417 3.682 21.860051 21.86 375.6523 375.7 112.511 112.5 45.4673 45.47 5.687524 5.7 7.555 7.6 8.235 8.2 0.03062 0.03 3.4125 3.41 41.86632 41.87 To one decimal place: 1.3511 1.4 2.473 2.5 To two decimal places: 22.494 22.50 79.2588 79.26 3. Solve the following problems and report answers with appropriate number of significant digits. 1) 6.201 cm + 7.4 cm + 0.68 cm +12.0 cm = 26.3 cm 1.2 x 103 or 1.20 x 103 or 1203 m 2) 1.6 km + 1.62 m +1200 cm = 3) 8.264 g - 7.8 g = 4) 10.4168 m - 6.0 m = 4.4 m 5) 12.00 m+15.001 kg= 6) 1.31 cm x 2.3 cm = 7) 5.7621 m x 6.201 m = 35.73 m2 0.5 g cant add m and kg 3.0 cm2 2.73 cm/s 8) 20.2 cm : 7.41 s = 9) 40.002 g : 13.000005 g = 3.0771 4. Express the following numbers in their equivalent standard notational form: 1) 123,876.3 1.238763 x 105 2) 1,236,840 1.23684 x 106 3) 422000 4.22000 x 105 4) 0.000000000000211 5) 0.000238 2.38 x 10-4 2.11 x 10-13 lOMoARcPSD|180 699 47 6) 0.0000205 2.05 x 10-5 5. Identify the sums or differences of the following: 1) (8.41 X 104) + (9.71 X 104) = 1.81 x 105 2) (5.11 X 102) - (4.2 X 102) = 91 3) (8.2 X 103) + (4.0 X 103) = -2 1.22 x 10 4 -2 4.2 x 10-2 4) (6.3 X 10 ) - (2.1 X 10 ) = 6. Express the product and the quotients of the following: 1) (3.56 X 105) (4.21 X 106) = 2) (2 X 107) (8 X 10-9) = 1.50 x 1012 0.2 3) (4.11 X 10-6) (7.51 X 10-4) = 3.09 x 10-9 4) 8.45 X 107 / 6.74 X 103 = 1.25 x 104 5) 9.7 X 108 / 8.6 X 10-2 = 1.1 x 1010 6) 4.7 X 10-2 / 5.7 X 10-6 = 8.2 x 103 1. d=vt (distance = velocity multiplied by time) d=9000 m t=12.12 sec. solving for v, v=d/t, v=742.57 m/sec. 2. d=vt d=528 m t=4 sec solving for v, v=d/t, v=132 m/sec. 3. d=vt v=96 m/sec. t=17 sec. d=1632 m 4. d=vt d=500,000 m v=700 m/sec. solving for t, t=d/v, t=714.3 sec.(11.9 min.) 5. d=vt d=350,000 m v=80,000 m/hr. solving for t, t=d/v t=4.375 hrs. 6. d=vt d=450,000 m v=120 m/sec solving for t, t=d/v, t=3750 sec. 7. d=vt d=1000m t=20 min.(60 sec.) =1200 sec. min solving for v, v=d/t, v=0.83 m/sec. 8. d=vt v=6 m/sec t=3 min.(60 sec.)=180 sec. min d=1080 m 9. d=vt d=816,000 m t=10 hrs.(60 min.)(60 sec.) = 36,000 sec. hrs min solving for v, v=d/t, v=22.67 m/sec. d=816,000 m t=10 hrs. solving for v, v=d/t, v=81.6 km/hr. or 10. d=v/t t=25 sec. v=1700 m/sec. d=68 m 11. d=v/t t=8 sec. v=60 m/sec. d=7.5 m