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Variación de Parámetros

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Variación
de
Parámetros
Definición
Ejercicio 1
𝑦´´ + 𝑦 = sec 2 𝑥
EHR
𝑦´´ + 𝑦 = 0
𝑦 = 𝑒 𝑚𝑥
𝑚2 + 1 = 0
𝑚 = 𝑎 ± 𝑏𝑖
𝑚2 = −1
𝑦 = 𝑒 𝑎𝑥 (𝐶1 cos 𝑏𝑥 + 𝐶2 sin 𝑏𝑥)
𝑚 = ± −1
𝑚 =0±𝑖
𝑚 = ±𝑖
𝑦 = 𝑒 0𝑥 (𝐶1 cos 𝑥 + 𝐶2 sin 𝑥)
𝑚= 𝑖
𝑦𝑐 = 𝐶1 cos 𝑥 + 𝐶2 sin 𝑥
𝑦𝑝 = 𝑢1 cos 𝑥 + 𝑢2 sin 𝑥
𝑢1 = −
𝑦2 𝑔(𝑥)
𝑑𝑥
𝑊
𝑦1 = cos 𝑥
𝑊=
cos 𝑥
−sin 𝑥
𝑢2 =
𝑦2 = sin 𝑥
sin 𝑥
cos 𝑥
= cos 𝑥 cos 𝑥 − sin 𝑥 (−sin 𝑥)
= cos 2 𝑥 + sin2 𝑥
=1
𝑦1 𝑔(𝑥)
𝑑𝑥
𝑊
𝑦1
𝑊 = 𝑦´
1
𝑦2
𝑦´2
𝑔 𝑥 = sec 2 𝑥
𝑦1 = cos 𝑥
𝑦2 = sin 𝑥
𝑢1 = −
𝑦2 𝑔(𝑥)
𝑑𝑥
𝑊
𝑢1 = −
sin 𝑥 sec 2 𝑥
𝑑𝑥
1
sec 𝑥 =
𝑢1 = −
sin 𝑥 sec 𝑥 sec 𝑥 𝑑𝑥
𝑢1 = −
1
(sin 𝑥)
(sec 𝑥) 𝑑𝑥
cos 𝑥
𝑢1 = −
𝑢1 = −
1
cos 𝑥
sin 𝑥
tan 𝑥 =
cos 𝑥
sin 𝑥
(sec 𝑥) 𝑑𝑥
cos 𝑥
sec 𝑥 tan 𝑥 𝑑𝑥
𝑔 𝑥 = sec 2 𝑥
𝑢1 = − sec 𝑥
𝑊=1
𝑦1 = cos 𝑥
𝑢2 =
𝑦1 𝑔(𝑥)
𝑑𝑥
𝑊
𝑢2 =
cos 𝑥 sec 2 𝑥
𝑑𝑥
1
𝑢2 =
cos 𝑥 sec 2 𝑥 𝑑𝑥
𝑢2 =
cos 𝑥 sec 𝑥 sec 𝑥 𝑑𝑥
𝑢2 =
sec 𝑥 𝑑𝑥
𝑢2 = ln sec 𝑥 + tan 𝑥
𝑦2 = sin 𝑥
𝑔 𝑥 = sec 2 𝑥
𝑊=1
1
sec 𝑥 =
→ cos 𝑥 sec 𝑥 = 1
cos 𝑥
𝑦𝑝 = 𝑢1 cos 𝑥 + 𝑢2 sin 𝑥
𝑢1 = − sec 𝑥
𝑢2 = ln sec 𝑥 tan 𝑥
𝑦𝑝 = − sec 𝑥 cos 𝑥 + ln sec 𝑥 tan 𝑥 sin 𝑥
𝑦𝑝 = −1 + ln sec 𝑥 tan 𝑥 sin 𝑥
𝑦𝑝 = sin 𝑥 ln sec 𝑥 + tan 𝑥 − 1
𝑦 = 𝑦𝑐 + 𝑦𝑝
𝑦𝑐 = 𝐶1 cos 𝑥 + 𝐶2 sin 𝑥
𝑦 = 𝐶1 cos 𝑥 + 𝐶2 sin 𝑥 + sin 𝑥 ln sec 𝑥 +tan 𝑥 − 1
1
sec 𝑥 =
cos 𝑥
Ejercicio 2
𝑦´´ − 𝑦 = 2 ln 𝑥
EHR
𝑦´´ − 𝑦 = 0
𝑦 = 𝑒 𝑚𝑥
𝑚2 − 1 = 0
𝑦1 = 𝑒 𝑥
(𝑚 − 1)(𝑚 + 1) = 0
𝑦2 = 𝑒 −𝑥
𝑚−1=0→ 𝑚 =1
𝑦𝑐 = 𝐶1 𝑒 𝑥 + 𝐶2 𝑒 −𝑥
𝑚 + 1 = 0 → 𝑚 = −1
𝑦𝑐 = 𝑢1 𝑒 𝑥 + 𝑢2 𝑒 −𝑥
𝑢1 = −
𝑦2 𝑔(𝑥)
𝑑𝑥
𝑊
𝑦1 = 𝑒 𝑥
𝑒𝑥
𝑊= 𝑥
𝑒
𝑢2 =
𝑦2 = 𝑒 −𝑥
𝑒 −𝑥
−𝑒 −𝑥
= 𝑒 𝑥 −𝑒 −𝑥 − (𝑒 −𝑥 )(𝑒 𝑥 )
= −𝑒 0 − 𝑒 0
= −1 − 1
= −2
𝑦1 𝑔(𝑥)
𝑑𝑥
𝑊
𝑦1
𝑊 = 𝑦´
1
𝑦2
𝑦´2
𝑔 𝑥 = 2 ln 𝑥
𝑦1 = 𝑒 𝑥
𝑦2 = 𝑒 −𝑥
𝑢1 = −
𝑦2 𝑔(𝑥)
𝑑𝑥
𝑊
𝑢1 = −
𝑒 −𝑥 2 ln 𝑥
𝑑𝑥
−2
𝑢1 =
𝑒 −𝑥 ln 𝑥 𝑑𝑥
𝑔 𝑥 = 2 ln 𝑥
𝑢2 =
𝑦1 𝑔(𝑥)
𝑑𝑥
𝑊
𝑢2 =
𝑒 −𝑥 2 ln 𝑥
𝑑𝑥
−2
𝑢2 = −
𝑒 𝑥 ln 𝑥 𝑑𝑥
𝑊 = −2
𝑦𝑝 = 𝑢1 𝑒 𝑥 + 𝑢2 𝑒 −𝑥
𝑢1 =
𝑒 −𝑥 ln 𝑥 𝑑𝑥
𝑦𝑝 = 𝑒 𝑥
𝑢2 = −
𝑒 −𝑥 ln 𝑥 𝑑𝑥 − 𝑒 −𝑥
𝑦 = 𝑦𝑐 + 𝑦𝑝
𝑦 = 𝐶1 𝑒 𝑥 + 𝐶2 𝑒 −𝑥 + 𝑒 𝑥
𝑒 𝑥 ln 𝑥 𝑑𝑥
𝑒 𝑥 ln 𝑥 𝑑𝑥
𝑦𝑐 = 𝐶1 𝑒 𝑥 + 𝐶2 𝑒 −𝑥
𝑒 −𝑥 ln 𝑥 𝑑𝑥 − 𝑒 −𝑥
𝑒 𝑥 ln 𝑥 𝑑𝑥
Ejercicio 3
𝑒 2𝑥
𝑦´´ − 4𝑦´ + 4𝑦 = 2
𝑥
EHR
𝑦´´ − 4𝑦´ + 4𝑦 = 0
𝑦 = 𝑒 𝑚𝑥
𝑚2 − 4𝑚 + 4 = 0
𝑦1 = 𝑒 2𝑥
(𝑚 − 2)(𝑚 − 2) = 0
𝑦2 = 𝑥𝑒 2𝑥
𝑚−2=0
𝑚=2
𝑦𝑐 = 𝐶1 𝑒 2𝑥 + 𝐶2 𝑥𝑒 2𝑥
𝑦𝑝 = 𝑢1 𝑒 2𝑥 + 𝑢2 𝑥𝑒 2𝑥
𝑢1 = −
𝑦2 𝑔(𝑥)
𝑑𝑥
𝑊
𝑦1 = 𝑒 2𝑥
2𝑥
𝑒
𝑊=
2𝑒 2𝑥
𝑢2 =
𝑦1 𝑔(𝑥)
𝑑𝑥
𝑊
𝑦2 = 𝑥𝑒 2𝑥
𝑥𝑒 2𝑥
𝑒 2𝑥 + 2𝑥𝑒 2𝑥
= 𝑒 2𝑥 𝑒 2𝑥 + 2𝑥𝑒 2𝑥 − (𝑥𝑒 2𝑥 )(2𝑒 2𝑥 )
= 𝑒 4𝑥 𝑥 + 2𝑥𝑒 4𝑥 − 2𝑥𝑒 4𝑥
= 𝑒 4𝑥
𝑦1
𝑊 = 𝑦´
1
𝑔 𝑥 =
𝑒 2𝑥
𝑥2
𝑦2
𝑦´2
𝑦1 =
𝑒 2𝑥
𝑢1 = −
𝑦2 =
𝑦2 𝑔(𝑥)
𝑑𝑥
𝑊
𝑥𝑒 2𝑥
𝑢1 = −
𝑢1 = −
𝑢1 = −
𝑒 2𝑥
𝑥 2 𝑑𝑥
𝑒 4𝑥
𝑥
𝑒 4𝑥 2
𝑥 𝑑𝑥
𝑒 4𝑥
1
𝑑𝑥
𝑥
𝑥𝑒 2𝑥
𝑔 𝑥 =
𝑢2 =
𝑒 2𝑥
𝑊 = 𝑒 4𝑥
𝑥2
𝑦1 𝑔(𝑥)
𝑑𝑥
𝑊
𝑒 2𝑥
𝑥 2 𝑑𝑥
4𝑥
𝑒 2𝑥
𝑢2 =
𝑒
𝑒 4𝑥
𝑢2 =
1
𝑥 2 𝑑𝑥
𝑒 4𝑥
𝑢2 =
1
𝑑𝑥
2
𝑥
𝑢2 =
𝑥 −2 𝑑𝑥
𝑢1 = − ln 𝑥
𝑥 −2+1
𝑢2 =
−2 + 1
𝑛+1
𝑥
𝑥 𝑛 𝑑𝑥 =
𝑛+1
𝑥 −1
𝑢2 =
−1
1
𝑢2 = −
𝑥
𝑦𝑝 = 𝑢1 𝑒 2𝑥 + 𝑢2 𝑥𝑒 2𝑥
𝑢1 = − ln 𝑥
1
𝑢2 = −
𝑥
1 2𝑥
𝑦𝑝 =
− 𝑥𝑒
𝑥
𝑦𝑝 = − ln 𝑥 𝑒 2𝑥 − 𝑒 2𝑥
− ln 𝑥 𝑒 2𝑥
𝑦 = 𝑦𝑐 + 𝑦𝑝
𝑦 = 𝐶1 𝑒 2𝑥 + 𝐶2 𝑥𝑒 2𝑥 − ln 𝑥 𝑒 2𝑥 − 𝑒 2𝑥
𝑦 = 𝐶1 𝑒 2𝑥 + 𝐶2 𝑥𝑒 2𝑥 − ln 𝑥 𝑒 2𝑥
𝑦𝑐 = 𝐶1 𝑒 2𝑥 + 𝐶2 𝑥𝑒 2𝑥
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