Subido por adolfo becke pacaya flores

examen fluidos

Anuncio
Adolfo Becker
𝑄 = 130
𝐿
1𝑚3
𝑚3
𝑥
= 2.17𝑥10−3
𝑚𝑖𝑛 60000𝐿/𝑚𝑖𝑛
𝑠
SC=0.86
𝜂 = 2𝑥10−2 𝑃𝑎. 𝑠
𝐷𝑖𝑛𝑡𝑒𝑟𝑖𝑜𝑟 = 62.7 𝑚𝑚 = 0.0627𝑚
R= 0.0314 m
𝐴 = 𝐴 = 𝜋𝑥𝑟 2 = 𝜋𝑥 0.0314 = 0.099𝑚2
V=Q/A=
2.17𝑥10−3
0.099
= 0.022
𝑚
𝑠
ESTRATEGIAS
A) 𝑁𝑅 =
𝑣𝐷
𝜂
=
0.022∗0.0627
2𝑥10−2
=
Descargar