Subido por Kevin Claudio

Ejercicio 2.90

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𝐹 = 𝑭𝑥 𝑖 + 𝑭𝑦 𝑗 + 𝑭𝑧 𝑘
𝐹 = 𝐹· λ
𝐹= 𝐹𝑥 +𝐹𝑦 +𝐹𝑧
𝐹 = 𝐹 · 𝐶𝑜𝑠𝜃𝑥 𝑖 + 𝐶𝑜𝑠𝜃𝑦 𝑗 + 𝐶𝑜𝑠𝜃𝑧 𝑘
λ = TEB = |EB
EB|
TEB
E (210, 400, 0) mm
B (480, 0, 600) mm
EB = 270i, -400j, 600k mm
EB =
𝑭𝑥 𝑖 2 + 𝑭𝑦 𝑗 2 + 𝑭𝑧 𝑘 2
𝟐𝟕𝟎𝟐 + (−𝟒𝟎𝟎)𝟐 +𝟔𝟎𝟎𝟐
𝟓𝟗𝟐𝟗𝟎𝟎
EB = 770 mm
EB
|EB|
Vector unitario =
270i −400j 600k
𝟕𝟕𝟎
600k
TEB = TEB · λ = (385 N ) 270i, −400j
𝟕𝟕𝟎
=135i, −200j, 300k N
𝑭𝒙 = 135 N
𝑭𝒚 = -200 N 𝑭𝒛 = 300 N
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