Subido por Gustavo Alonso Fuentes Parra

Examples Yield 02

Anuncio
EXAMPLE 6-13:
—
50, <ryv = 70, and
A point in a structural component has a stress state given by
Tn, = 200 MPa. The materia] of the component is ductile and has yield strength of
300 MPa. Will the material yield at the point under consideration according to the
maximum shear stress theory?
Answer: The given stress state is a biaxial state of stress. Hence the two in-plane
principal normal stresses can be determined using Eqs. (6.47) as
a,,
=> iT|
= 260 MPa,
<72
(j3
--p?±1/p-ÿ)3+T?„
= —1 40 MPa
The third principal stress u., - 0. (Note that according to convention, the principal
stress ff]t <T:,
should be ordered as (r, > (T2 > (i*. However, we have not followed
the convention only for this example. You may follow the convention and renumber the
principal stresses, and draw the yield plot axes accordingly.)
The principal stress state (<T|t
= (260, — 140) can be plotted on the biaxial yield
plot to determine the yield condition. The stress state at the point lies outside the yield
locus as shown in Figure Eb-13. Hence yielding occurs.
CM Pa)
300
-300
300
* (260,-140)
-300
FIGURE Efr-13
n, (MPa)
EXAMPLE 6-14;
Determine the yield condition at the point mentioned in Example 6- 1 3, using the
maximum normal stress theory.
Answer: The maximum normal stress theory states that yielding occurs only when
any principal normal stress equals or exceeds the yield strength in a simple tension test,
Hence this theory predicts that no yielding occurs. This result is also shown graphically
in Figure E6-I4, where the stress state lies within the yield locus.
This example further demonstrates that the maximum normal stress theory can give
erroneous results for ductile materials.
<T2 (MPa)
300
300
300
(260,-140)
-300
FIGURE Efr-14
<r, (MPa)
Descargar