Simulació d’experiments SternGerlach consecutius Lluís Garrido [email protected] http://www.ecm.ub.es/~garrido Spin 1/2 1 La simulació.... +h/2 P1 | S z ,+ > → −h/2 x gen x=0 P1 Si x =1 1 − P1 xgen < P1 +h/2 recordatori PA|ϕ > (an ) =|< an | ϕ >|2 < A >|ϕ > =< ϕ | A | ϕ > ∆ |ϕ > A = < ϕ | A2 | ϕ > − < ϕ | A | ϕ > 2 2 La simulació.... PS x |S z , + > (+h / 2) =|< S x ,+ | S z ,+ >|2 = 1 / 2 < S x >|S z , + > =< S z ,+ | S x | S z ,+ >= 0 | S z ,+ > → ∆ |S z , x > S x = < S z ,+ | S x2 | S z ,+ > − < S z ,+ | S x | S z ,+ > 2 = h / 2 PS x |S z , + > (−h / 2) =|< S x ,− | S z ,+ >|2 = 1 / 2 h 2 h 2 µ = 4982 − 5018 = −0.0036 h 2 2 h h 4982 + 5018 − µ2 ≈ 10000 2 2 σ= 1 h − 0.0036 ± 10000 2 Spin 1/2 d̂ cos(θ / 2) | S dˆ ,+ >= iφ e sin( θ / 2 ) − e −iφ sin(θ / 2) | S dˆ ,− >= cos(θ / 2) 3 observables − iφ h cos(θ ) e sin(θ ) S dˆ = iφ 2 e sin(θ ) − cos(θ ) Spin 1 cos (θ / 2) | S dˆ ,1 >= e iφ sin(θ ) / 2 e 2iφ sin 2 (θ / 2) 2 − e −iφ sin(θ ) / 2 | S dˆ ,0 >= cos(θ ) iφ e sin( θ ) / 2 1 2 (−1 + cos(θ ))(i cos(φ ) + sin(φ )) 2 | S dˆ ,−1 >= − e −iφ sin(θ ) / 2 2 cos (θ / 2) 4 Observable cos(θ ) S dˆ = h e iφ sin(θ ) / 2 0 | e − iφ sin(θ ) / 2 0 e iφ sin(θ ) / 2 0 − iφ e sin(θ ) / 2 − cos(θ ) Simulacions per spin 1/2 θ = φ = 450 5 Simulacions per spin 1 θ = φ = 450 6