Tema 7: Método de Intersección Simple

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A + C + α + β + B = 400 g
A + C = 400 g − (α + β + B)
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2
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2
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sen C
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A + C + α + β + B = 400 g
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C = (400 − B − β − α ) − A = E − A
D BA ⋅ sen A ⋅ sen β = D CB ⋅ sen C ⋅ sen α
D BA ⋅ sen A ⋅ sen β = D CB ⋅ sen(E − A) ⋅ sen α
[
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D BA ⋅ sen A ⋅ sen β = D CB ⋅ sen E ⋅ cos A − cos E ⋅ sen A ⋅ sen α
[
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sen A ⋅ D BA ⋅ sen β + BC ⋅ sen α ⋅ cos E = D CB ⋅ sen α ⋅ sen E ⋅ cos A
tg A =
D CB ⋅ sen α ⋅ sen E
D BA ⋅ sen β + D CB ⋅ sen α ⋅ cos E
C=E−A
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θ AP = θ AB + Aˆ
θ CP = θ BC ± 200 − Cˆ
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B 2 = 200 − C − β
B 2 = B − B1
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D BA
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sen A sen α
D AB
D AP
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X p = X A + D AP ⋅ senθ AP
X p = X C + DCP ⋅ senθ CP
YP = Y A + D AP ⋅ cosθ AP
YP = YC + DCP ⋅ cosθ CP
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∆H PC = t PC + i P − mC + C (e + r )
∆H PA = t PA + i P − m A + C (e + r )
∆H PB = t PB + i P − m B + C (e + r )
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